LAWS OF MOTION-QnA

A carefully structured set of Laws of Motion questions can turn a difficult chapter into a scoring opportunity for Class 11 students. This QnA collection moves from simple definitions to higher order derivations and applications so that learners gradually build conceptual clarity and numerical confidence. Short 1 marker and 2 marker items sharpen memory and formula recall, while 3 , 4 and 5 marker descriptive questions train students to present stepwise reasoning, draw on Newton’s laws, friction, circular motion, and momentum conservation, and express answers in exam style language. Together, these questions provide ready to use practice for school tests, board pattern examinations, and competitive exams that rely heavily on this foundational chapter. Teachers can also use the set for rapid quizzes, homework, and revision worksheets to track progress and close conceptual gaps early in the term.

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TRIGONOMETRIC FUNCTIONS-Exercise 3.1

Exercise • Jan 2026

Trigonometric Functions form a crucial foundation of higher mathematics and play a vital role in physics, engineering, astronomy, and real-life proble...

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LAWS OF MOTION

by Academia Aeternum

1-2 liner Questions

Q1: Define inertia.

Inertia is the tendency of a body to resist any change in its state of rest or of uniform motion in a straight line. The greater the mass, the greater is the inertia of the body.


Q2: State Newton’s first law of motion.

Newton’s first law states that a body remains at rest or in uniform motion in a straight line unless acted upon by an external unbalanced force. This law introduces the concept of inertia.


Q3: Write the mathematical form of Newton’s second law.

Newton’s second law is written as \( \vec{F}_{\text{net}} = m\vec{a} \), where \( \vec{F}_{\text{net}} \) is net external force, \(m\) is mass, and \( \vec{a} \) is acceleration produced in the body.


Q4: What is linear momentum?

Linear momentum of a particle is the product of its mass and velocity, \( \vec{p} = m\vec{v} \). It is a vector quantity directed along the velocity of the particle.


Q5: Define impulse of a force.

Impulse is the product of a large force and the short time interval for which it acts, \( J = F\Delta t \). It is equal to the change in linear momentum of the body.


Q6: State Newton’s third law of motion.

Newton’s third law states that for every action there is an equal and opposite reaction. Action and reaction forces always act on two different interacting bodies.


Q7: What is meant by an external force?

An external force on a system is a force exerted by a body outside the system’s boundary. Only external forces can change the total momentum of the system.


Q8: Define coefficient of kinetic friction.

The coefficient of kinetic friction \( \mu_k \) is the ratio of kinetic friction \( F_k \) to normal reaction \( N \), that is \( \mu_k = F_k/N \). It is dimensionless and depends on the nature of surfaces in contact.


Q9: What is centripetal force?

Centripetal force is the net inward force required to keep a body moving in a circular path of radius \( r \) with speed \( v \). Its magnitude is \( F_c = mv^2/r \) and it is directed towards the centre of the circle.


Q10: Give one example of rolling friction.

When a car tyre rolls over the road, the resistive force opposing its motion is rolling friction. Rolling friction is generally smaller than kinetic friction for the same pair of surfaces.


Q11: State the law of conservation of linear momentum.

The total linear momentum of an isolated system of interacting particles remains constant in time, if no external force acts on the system. Internal forces cannot change the total momentum.


Q12: What is a free-body diagram (FBD)?

A free-body diagram is a simplified sketch of an object showing only the object and all the external forces acting on it. Drawing an FBD helps in applying Newton’s laws systematically.


Q13: Define equilibrium of a particle.

A particle is said to be in equilibrium when the vector sum of all forces acting on it is zero. In this condition, the particle has no acceleration.


Q14: Write the SI unit of force and define it.

The SI unit of force is newton (N). One newton is the force that produces an acceleration of \( 1 \,\text{m s}^{-2} \) in a body of mass \( 1 \,\text{kg} \).


Q15: What is limiting friction?

Limiting friction is the maximum value of static friction just before the body on a surface starts sliding. It equals \( \mu_s N \), where \( \mu_s \) is the coefficient of static friction and \( N \) is normal reaction.


Short answer Questions

Q1: A force of 20 N acts on a body of mass 5 kg at rest on a frictionless surface. Find the acceleration produced.

Using Newton’s second law, \( a = F/m = 20/5 = 4 \,\text{m s}^{-2} \). The body starts moving in the direction of the applied force with this acceleration.


Q2: A body of mass 3 kg moves with velocity 6 m s\(^{-1}\). Calculate its momentum and state the direction of momentum.

Momentum \( p = mv = 3 \times 6 = 18 \,\text{kg m s}^{-1} \). The direction of momentum is the same as the direction of the velocity vector of the body.


Q3: Distinguish between static and kinetic friction.

Static friction acts when a body is at rest and opposes the initiation of motion, increasing from zero up to a limiting value. Kinetic friction acts when the body is sliding, has nearly constant magnitude, and is usually smaller than the limiting static friction.


Q4: Why is it easier to push a loaded trolley after it has started moving than to start it from rest?

To start motion, the applied force must overcome limiting static friction, which is relatively large. Once the trolley is in motion, only kinetic friction, which is smaller, needs to be balanced, so a smaller force is sufficient.


Q5: State two differences between mass and weight.

Mass is the amount of matter in a body, is scalar, and remains constant everywhere, measured in kilograms. Weight is the gravitational force on the body, is vector, depends on local acceleration due to gravity, and is measured in newtons.


Q6: A 2 kg block is pulled on a horizontal frictionless table by a force of 10 N making an angle of \( 60^\circ \) with the horizontal. Find the horizontal component of the force and the acceleration.

Horizontal component \( F_x = 10\cos60^\circ = 5 \,\text{N} \). Acceleration \( a = F_x/m = 5/2 = 2.5 \,\text{m s}^{-2} \) along the table.


Q7: Explain why passengers tend to fall forward when a moving bus stops suddenly.

When the bus stops abruptly, the lower parts of passengers’ bodies in contact with the bus decelerate quickly. Due to inertia of motion, the upper parts continue to move forward, so passengers appear to fall forward.


Q8: A body of mass 0.5 kg experiences a change in velocity from 4 m s\(^{-1}\) to 10 m s\(^{-1}\) in 3 s. Find the average force acting on it.

Change in momentum \( \Delta p = m(v - u) = 0.5(10 - 4) = 3 \,\text{kg m s}^{-1} \). Average force \( F = \Delta p/\Delta t = 3/3 = 1 \,\text{N} \) in the direction of motion.


Q9: Why does a cyclist lean inward while taking a turn on a circular track?

During turning, the needed centripetal force is provided by the horizontal component of the normal reaction between tyres and road. By leaning inward, the cyclist aligns the resultant of weight and normal reaction towards the centre, preventing toppling.


Q10: Briefly explain why seat belts are important in cars using Newton’s laws.

In a sudden stop, the car’s body decelerates quickly, but the passengers’ bodies tend to continue forward because of inertia. A properly fastened seat belt provides a restraining force over a short distance, reducing acceleration and the risk of injury.


Long answer Questions

Q1: State and explain Newton’s first law of motion with an everyday example.

Newton’s first law states that a body continues in its state of rest or uniform straight-line motion unless acted upon by an external unbalanced force. For example, when a bus at rest suddenly starts, passengers tend to fall backward because their bodies tend to remain at rest while the bus moves forward; the backward fall is due to inertia of rest. This law justifies why a book lying on a table remains there indefinitely until someone applies a force to move it.


Q2: Show that impulse is equal to change in momentum and state one situation where impulse is useful.

Let a constant force \( F \) act on a body for a short time \( \Delta t \), producing acceleration \( a \). From Newton’s second law, \( F = \Delta p/\Delta t \), where \( \Delta p \) is change in momentum. Rearranging gives \( F\Delta t = \Delta p \); the left side is defined as impulse \( J \). Hence impulse equals the change in momentum produced. In sports like cricket, a fielder moves hands backward while catching a fast ball so that the time of impact increases, reducing the average force even though the impulse and momentum change remain the same.


Q3: Explain the terms static friction, kinetic friction and rolling friction.

Static friction acts between two surfaces in contact when there is no relative motion; it adjusts up to a limiting value to oppose impending motion. Kinetic friction acts when surfaces slide over each other and usually has a nearly constant value smaller than limiting static friction. Rolling friction arises when a body such as a wheel or ball rolls over a surface and is typically much smaller than kinetic friction, which is why vehicles use wheels to move efficiently.


Q4: What is centripetal force? Derive its expression for a body of mass \( m \) moving with speed \( v \) in a circle of radius \( r \).

When a body moves in a circular path at constant speed, its velocity continuously changes direction, so an inward acceleration called centripetal acceleration acts on it. For uniform circular motion, this acceleration has magnitude \( a_c = v^2/r \) directed towards the centre. Using Newton’s second law, the required inward or centripetal force is \( F_c = ma_c = mv^2/r \). This force may be provided by tension in a string, friction between tyres and road, or other interactions depending on the situation.


Q5: Explain the law of conservation of linear momentum for a system of two interacting bodies with one example.

Consider two bodies that exert equal and opposite internal forces on each other according to Newton’s third law. These internal forces produce equal and opposite changes in their momenta, so the vector sum of their momenta remains constant as long as no external force acts on the system. For instance, when a gun fires a bullet, the bullet gains forward momentum and the gun gains an equal backward momentum (recoil); the total momentum of gun plus bullet just before and just after firing remains the same.


Descriptive Questions

Q1: Describe in detail the different kinds of friction and discuss their advantages and disadvantages in daily life.

Friction is a resistive force that opposes the relative motion or tendency of motion between two surfaces in contact. Static friction acts when there is no relative motion and adjusts itself from zero up to a limiting value, preventing sliding until the applied force exceeds this limit. Kinetic or sliding friction comes into play once motion has started; its magnitude is nearly constant and is usually slightly less than the limiting static friction for the same pair of surfaces. Rolling friction occurs when one body rolls over another, as in wheels or ball bearings, and is the smallest of the three because there is less microscopic interlocking of surface irregularities. Friction is useful because it enables walking without slipping, allows vehicles to move and stop, and helps us hold objects firmly. However, it also has disadvantages: it causes wear and tear of machine parts, produces unwanted heating, and wastes energy, so lubrication and smooth bearings are often used to reduce excessive friction while retaining enough grip for safe operation.


Q2: Discuss the motion of a car on a level circular road and explain the role of friction and speed limits using Newton’s laws.

When a car moves on a level circular road, it must experience an inward centripetal force to stay on the curved path. This inward force is provided by the horizontal component of static friction between the tyres and the road; if this friction is insufficient, the tyres will skid outward and the car will leave the circular track. As the speed of the car increases, the required centripetal force \( mv^2/r \) increases rapidly because it is proportional to the square of speed, while the maximum available frictional force is limited by \( \mu_s N \), where \( \mu_s \) is the coefficient of static friction and \( N \) is the normal reaction. Therefore, for a given road and weather condition, there is an upper speed beyond which friction cannot supply the required centripetal force, which is why speed limits are imposed on sharp turns, especially when the road is wet or covered with sand. Drivers who understand this connection between friction and centripetal force intuitively slow down on curves to avoid skidding.


Q3: Explain with reasoning why a rocket can move forward in space where there is no air, using Newton’s laws of motion.

A rocket carries fuel that, when burnt, ejects exhaust gases at very high speed backward through its nozzle. According to Newton’s third law, the backward momentum of the exhaust gases is accompanied by an equal and opposite forward momentum of the rocket, so the rocket experiences a forward thrust force. Since space is nearly free of external forces like air resistance and friction, the rocket and exhaust gases together form an almost isolated system, and the law of conservation of linear momentum applies. The continuous ejection of gases keeps increasing the forward momentum and speed of the rocket even though there is no surrounding medium to “push against”, which is often misunderstood in everyday thinking.


Q4: Describe how seat belts and airbags in cars reduce injuries during collisions using the concept of impulse and Newton’s second law.

In a collision, the velocity of a car and its occupants changes rapidly, leading to a large change in momentum in a very short time. The impulse experienced by an occupant is fixed by this momentum change, but the average force can be reduced if the time over which the change occurs is increased. Seat belts restrain the body and stretch slightly, and airbags inflate to provide a soft, cushioning surface that compresses as the body moves forward. This combination increases the duration of impact from a few milliseconds to a slightly longer period, so by Newton’s second law the average force \( F = \Delta p/\Delta t \) becomes smaller. As a result, the deceleration of the body is less severe and the risk of serious injury to the chest, head, and neck is greatly reduced, which is why modern safety standards insist on proper use of these devices.


Q5: Using an example of a person walking, explain how Newton’s third law and friction together make forward motion possible.

When a person walks, each foot pushes the ground backward with a certain horizontal force at every step. According to Newton’s third law, the ground simultaneously exerts an equal and opposite horizontal reaction force on the foot, directed forward. This forward reaction force, provided by static friction between the shoe and the ground, accelerates the person’s body and produces forward motion. If the surface is extremely smooth or oily, the coefficient of static friction becomes very small, so the necessary reaction force cannot be generated and the person slips instead of walking steadily. Thus, comfortable walking depends on having enough friction so that the action–reaction pair can effectively propel the body forward.


Frequently Asked Questions

Newton's First Law states that a body remains at rest or in uniform straight-line motion unless acted upon by a net external force; this is called the law of inertia.

Newton's Second Law states that the rate of change of momentum of a body is proportional to the applied net force and takes place in the direction of the force, \(\vec{F} = \frac{d\vec{p}}{dt} = m\vec{a}\).

Newton's Third Law states that for every action there is an equal and opposite reaction; forces always occur in pairs acting on different bodies.

Inertia is the property of a body by virtue of which it resists any change in its state of rest or uniform motion in a straight line.

Linear momentum \(\vec{p}\) of a body is defined as the product of its mass and velocity, \(\vec{p} = m\vec{v}\).

Impulse of a force is the product of force and the time for which it acts and is equal to the change in momentum, \(I = F\Delta t = \Delta p\).

In an isolated system with no external force, the total linear momentum of the system remains constant during any interaction.

For constant mass, Newton's Second Law reduces to \(\vec{F}_{net} = m\vec{a}\).

An inertial frame is a reference frame in which Newton's First Law holds, i.e., a frame that is either at rest or moving with uniform velocity.

A non-inertial frame is a reference frame that is accelerating with respect to an inertial frame, in which fictitious or pseudo forces must be introduced to apply Newton's laws.

Pseudo force is an apparent force introduced in a non-inertial frame of reference, given by \(\vec{F}_{pseudo} = -m\vec{a}_{frame}\), acting opposite to the acceleration of the frame.

Normal reaction is the contact force exerted by a surface on a body, acting perpendicular to the surface.

Friction is the contact force that opposes the relative motion or the tendency of relative motion between two surfaces in contact.

Static friction acts between surfaces at rest relative to each other and can vary up to a limiting value, while kinetic friction acts when surfaces slide over each other with relative motion.

Limiting friction is the maximum value of static friction just before the body begins to move relative to the surface.

Kinetic friction is given by \(f_k = \mu_k N\), where \(\mu_k\) is the coefficient of kinetic friction and \(N\) is the normal reaction.

Static friction satisfies \(f_s \leq \mu_s N\), where \(\mu_s\) is the coefficient of static friction.

The coefficient of friction is the ratio of limiting friction to normal reaction, \(\mu = \frac{f_{lim}}{N}\); it is dimensionless.

Angle of repose is the maximum angle of an inclined plane with the horizontal at which a body just begins to slide; \(\tan\theta = \mu_s\).

Static friction adjusts its magnitude to match the applied force (up to its limit) so that the body remains at rest, hence it is called self-adjusting.

Rolling friction is the resistive force that opposes the motion of a rolling body on a surface and is generally much smaller than sliding friction.

Sliding friction is generally greater than rolling friction for the same pair of surfaces.

Centripetal force is the net force required to keep a body in uniform circular motion and is directed towards the center, \(F_c = \frac{mv^2}{r}\).

A car turning on a level road and a cyclist taking a turn on a flat track use friction between tyres and road to provide centripetal force.

Banking of roads means raising the outer edge of a curved road to provide a component of normal reaction towards the center to act as centripetal force.

For a frictionless banked curve, \(\tan\theta = \frac{v^2}{rg}\), where \(\theta\) is banking angle, \(v\) speed, \(r\) radius, and \(g\) acceleration due to gravity.

Apparent weight is the normal reaction experienced by a body, which may differ from true weight \(mg\) in accelerating frames like lifts.

In a lift accelerating up: \(N = m(g + a)\); accelerating down: \(N = m(g - a)\); in free fall: \(N = 0\).

Due to inertia, the lower body moves with the bus while the upper body tends to remain at rest, so the passenger feels a backward push relative to the bus.

Due to inertia of motion, the upper body continues to move forward while the bus and feet come to rest, causing the passenger to lurch forward.

Mass is the quantity of matter and measure of inertia (scalar, SI unit kg), while weight is the gravitational force acting on mass, \(W = mg\) (vector, SI unit newton).

Contact forces act via physical contact (normal, friction, tension), while non-contact forces act at a distance (gravitational, electrostatic, magnetic).

Tension is the pulling force transmitted along a stretched string, rope, or cable, equal in magnitude at all points for a light, inextensible string in equilibrium.

For two masses \(m_1\) and \(m_2\) pulled by force \(F\), acceleration \(a = \frac{F}{m_1 + m_2}\) and tension can be found from \(T = m_1 a\) or \(T = F - m_2 a\).

Atwood's machine consists of two masses connected over a light frictionless pulley; acceleration \(a = \frac{(m_2 - m_1)g}{m_1 + m_2}\) (assuming \(m_2 > m_1\)).

Pulling at an angle reduces normal reaction and hence friction, while pushing at an angle increases normal reaction and friction, so pulling is easier.

Isolate the body, represent it as a point or simple shape, show all external forces with correct directions and labels, and choose a convenient coordinate system.

For each body, write \(\sum F_x = m a_x\) and \(\sum F_y = m a_y\) from its FBD, then solve the system of equations for unknowns like acceleration and tension.

Newton's Second Law quantitatively relates force, mass, and acceleration, while the First and Third Laws can be derived or understood using it, so it is considered the fundamental law.

Before firing, total momentum is zero; after firing, forward momentum of bullet equals backward momentum of gun so total remains zero, causing gun recoil.

Rockets expel gases backward at high speed; by conservation of momentum, the rocket gains forward momentum even in vacuum.

In a sudden stop, car decelerates but passenger tends to continue forward due to inertia; seatbelts provide restraining force, reducing injuries.

Friction between foot and ground prevents slipping, providing reaction force that pushes the body forward as the person exerts backward force on the ground.

A particle is in equilibrium when the vector sum of all forces on it is zero, so its acceleration is zero.

For a particle: \(\sum F_x = 0\) and \(\sum F_y = 0\); for rigid bodies (beyond this chapter), \(\sum \tau = 0\) is also used.

If \(F > \mu_k N\), acceleration \(a = \frac{F - \mu_k N}{m}\); if \(F \leq \mu_s N\), the block does not move and \(a = 0\).

For a block of mass \(m\) on an incline angle \(\theta\), components of weight are \(mg\sin\theta\) down the plane and \(mg\cos\theta\) normal; friction opposes motion along the plane.

On a smooth (frictionless) incline of angle \(\theta\), acceleration down the plane is \(a = g\sin\theta\).

Key topics include Newton's laws, friction (graphs and coefficients), circular motion and banking, connected bodies and pulleys, pseudo force, and conservation of momentum with numericals.

Draw FBDs for each mass, define directions of acceleration, apply \(F = ma\) equations consistently, use string constraints for equal accelerations where required, then solve algebraically.

Typical questions include calculating friction on horizontal and inclined planes, proving angle of repose relation, explaining self-adjusting nature, and comparing static and kinetic friction.

Laws of motion form the base for advanced mechanics topics like work-energy, circular motion, gravitation, and are heavily used in higher-level problem solving in competitive exams.

Area under a force–time graph gives impulse, which equals change in momentum; numericals often ask to compute impulse from such graphs.

Clearly indicate directions with sign convention, use unit vectors for components, and avoid mixing scalar and vector forms in the same equation.

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