Class X · Chapter 12 · NCERT Mathematics

CHAPTER 12

Surface Areas and Volumes

Three-Dimensional Mensuration

Cones on cylinders, spheres in cubes — the geometry of the world we live in.

\(V(Frustum) = πh/3·(r₁²+r₂²+r₁r₂)\)
12 CBSE Marks
Difficulty
9 Topics
Very High Board Weight

Topics Covered

9 key topics in this chapter

Cube, Cuboid, Cylinder: Revision
Cone: CSA, TSA, Volume
Sphere & Hemisphere: SA, Volume
Combination of Solids
Frustum of a Cone
CSA & Volume of Frustum
Conversion of Solids
Melting & Recasting
Real-Life Applications

Study Resources

Key Formulas

Formula / Rule Expression
Cylinder CSA \(2πrh\)
Cylinder TSA \(2πr(h+r)\)
Cone CSA \(πrl (l = slant height = √(r²+h²))\)
Cone Volume \(⅓πr²h\)
Sphere SA \(4πr²\)
Sphere Volume \(⁴⁄₃πr³\)
Hemisphere CSA \(2πr²\)
Hemisphere TSA \(3πr²\)
Frustum CSA \(π(r₁+r₂)l (l = √[h²+(r₁−r₂)²])\)
Frustum Volume \(πh/3·(r₁²+r₂²+r₁r₂)\)

Important Points to Remember

For a combination of solids, add the surface areas of visible faces only — do not add hidden/joined areas.
For volume of a combination, simply add the volumes of all constituent solids.
Frustum: formed by cutting a cone with a plane parallel to its base.
When a solid is melted and recast, volume is conserved (not surface area).
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