111121133114641Pascal's TriangleⁿCᵣ + ⁿCᵣ₋₁ = ⁿ⁺¹Cᵣ
Chapter 6 · Class XI Mathematics · NCERT Exercises

Permutations & Combinations — Exercises

Count Every Arrangement — 42 P&C Problems with Full Reasoning

📂 5 Exercises 📝 42 Questions 🎓 High

Exercise Index

5 exercise files · 42 total questions

Chapter at a Glance

JEE MainJEE AdvancedCBSE BoardsBITSATKVPY
11Concepts
15Formulas
HighDifficulty
7–9%Weightage

Before You Begin

Prerequisites

  • Multiplication principle
  • Factorial arithmetic
  • Sets — for selection logic

Have Ready

  • 🔧Rough paper for listing (small cases)
  • 🔧Calculator for large factorials

Exercise Topic Map

Exercise 6.1Count paths/codes/choices using FCP: total = product of choices
Exercise 6.2Evaluate n!; simplify n!/(n−2)!; find n given factorial equation
Exercise 6.3ⁿPᵣ; arrange letters; objects always/never together
Exercise 6.4ⁿCᵣ; committees; ⁿCᵣ=ⁿCₙ₋ᵣ; Pascal's identity
MiscellaneousCircular (n−1)!; necklace ÷2; alphabetical rank; at-least-one

Key Formulae

\(^nP_r = \dfrac{n!}{(n-r)!}\)
\(^nC_r = \dfrac{n!}{r!\,(n-r)!} = {}^nC_{n-r}\)
\(\text{Circular} = (n-1)!\)
\(^nC_r + {}^nC_{r-1} = {}^{n+1}C_r \text{ (Pascal)}\)
\(\text{At-least-one} = \text{Total} - \text{(none selected)}\)

NCERT Solving Method

Step 1 — Ask 'Does ORDER matter?' Yes→Permutation, No→Combination. Step 2 — Restricted: fix constrained objects first, arrange rest. Step 3 — 'Always together': treat group as 1 unit, arrange, then internally arrange. Step 4 — 'Never together': Total − (arrangements where they ARE together). Step 5 — Rank of word: count letters alphabetically less than each position.

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