Motion in a Plane — Class XI Physics Chapter 4 | Academia Aeternum
Class XI Physics  ·  Chapter 4

Motion in a Plane

NCERT | Class 11 | Physics

The world is not a straight line. Vectors, projectiles, and circular motion — this chapter puts the curve into physics.

\(\vec{A} + \vec{B} = \vec{R}\)
2D
Motion Type
3
Types of Vectors
32
NCERT Exercises
R = u²sin2θ/g
Range Formula
JEE
Critical Chapter

Conceptual Framework

Core Topics at a Glance

Scalars & Vectors
Scalars have magnitude only; vectors have magnitude and direction. Addition of vectors follows the triangle/parallelogram law, not simple arithmetic.
\(R = \sqrt{A^2+B^2+2AB\cos\theta}\)
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Resolution of Vectors
Any vector can be resolved into two perpendicular components. This is the cornerstone of 2D and 3D mechanics.
\(A_x = A\cos\theta,\; A_y = A\sin\theta\)
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Dot & Cross Products
Scalar (dot) product gives a scalar: A·B = AB cosθ. Vector (cross) product gives a vector perpendicular to both: |A×B| = AB sinθ.
\(\vec{A}\cdot\vec{B} = AB\cos\theta\)
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Projectile Motion
Horizontal velocity is constant; vertical motion is free fall. The trajectory is a parabola. Maximum range occurs at 45°.
\(R = u^2\sin2\theta/g\)
Uniform Circular Motion
Speed is constant but velocity changes direction continuously. Centripetal acceleration is always directed toward the centre.
\(a_c = v^2/r = \omega^2 r\)
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Relative Motion in 2D
Velocity of A relative to B is vector subtraction. Key applications: river-boat problems, rain-umbrella, and aircraft navigation.
\(\vec{v}_{AB} = \vec{v}_A - \vec{v}_B\)

Quick Reference

Key Formulae

QuantityFormulaRemarks
Resultant Magnitude\(R = \sqrt{A^2+B^2+2AB\cos\theta}\)Parallelogram law
Resultant Angle\(\tan\phi = \frac{B\sin\theta}{A+B\cos\theta}\)Angle with A
Max Height\(H = \frac{u^2\sin^2\theta}{2g}\)Projectile
Time of Flight\(T = \frac{2u\sin\theta}{g}\)Projectile
Range\(R = \frac{u^2\sin 2\theta}{g}\)R_max at θ=45°
Centripetal Acc.\(a_c = \frac{v^2}{r} = \omega^2 r\)Uniform circular motion
Angular Velocity\(v = r\omega\)Relation to linear speed
Period\(T = \frac{2\pi r}{v} = \frac{2\pi}{\omega}\)Circular motion

Exam-Ready Insights

Important Points to Remember

01

Triangle law: if two vectors are represented by two sides of a triangle, the resultant is the closing side (head to tail).

02

At maximum height in projectile, vertical velocity = 0 but horizontal velocity = u cosθ (unchanged).

03

Range is same for complementary angles (θ and 90°−θ). Range is maximum at θ = 45°.

04

Centripetal force is not a new type of force — it is the net force directed toward the centre provided by existing forces (tension, gravity, normal).

05

A×B = −B×A — cross product is anti-commutative. A·B = B·A — dot product is commutative.

06

In river-boat problems, to cross in minimum time, boat must be directed perpendicular to the river (not considering drift).

Competitive Exams

Exam Corner

Motion in a Plane is tested across all major competitive examinations. Here are the most frequently tested topics:

⚡ JEE Main🔷 JEE Advanced🟢 NEET🟡 CBSE Board
AllProjectile motion — range, height, time
JEEVector addition and components — numerical
NEETCentripetal acceleration and force
JEERelative velocity in 2D — river-boat
BoardDerivation of range & max height
JEEDot and cross product — applications
AllUniform circular motion — conceptual

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