Shaded area = ∫(upper−lower)dx
Chapter 8 · Class XII Mathematics · NCERT Exercises

Application of Integrals — Exercises

Area Under Curves, Between Curves — Every Solution Fully Worked Out

📂 3 Exercises 📝 39 Questions 🎓 Moderate-High

Exercise Index

3 exercise files · 39 total questions

Chapter at a Glance

JEE MainCBSE BoardsBITSAT
6Concepts
6Formulas
Moderate-HighDifficulty
5–6%Weightage

Before You Begin

Prerequisites

  • ✓Ch 7 — Integrals (definite integral evaluation)
  • ✓Class XI — Conic Sections (Ch 10)
  • ✓Graph sketching of standard curves

Have Ready

  • 🔧Graph paper
  • 🔧Sketch of standard curves: line, parabola, circle, ellipse

Syllabus-wise Topic Map

8.1 IntroductionDefinite integral reinterpreted geometrically as signed area
8.2 Area under Simple CurveA=∫ₐᵇy\,dx for area between a curve and the x-axis (or y-axis); area between two curves using ∫(y_upper−y_lower)dx

Key Formulae

\(A = \int_a^b y\,dx\ \text{(area under curve, above x-axis)}\)
\(A = \int_a^b \big(f(x)-g(x)\big)\,dx\ \text{(between two curves)}\)
\(\text{Circle }x^2+y^2=a^2:\ \text{Area (quadrant)} = \dfrac{\pi a^2}{4}\)
\(\text{Always sketch the region before setting up limits}\)

NCERT Solving Method

Step 1 — Sketch the curves and shade the required region before writing any integral. Step 2 — Find points of intersection algebraically to fix the limits of integration. Step 3 — Identify the upper and lower curve on the interval; set up A=∫(upper−lower)dx. Step 4 — If the region changes shape (upper/lower curve swaps) partway, split the integral at that x-value. Step 5 — Take the absolute value of area below the x-axis.

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