Class IX · Chapter 8 · NCERT Mathematics

CHAPTER 08

Quadrilaterals

Parallelograms & Mid-Point Theorem

Four sides contain a world of properties — the diagonal is the key that unlocks them all.

\(∠A + ∠B + ∠C + ∠D = 360°\)
9 CBSE Marks
Difficulty
8 Topics
High Board Weight

Topics Covered

8 key topics in this chapter

Angle Sum Property of Quadrilaterals
Types of Quadrilaterals
Properties of Parallelogram
Diagonals of Parallelogram
Conditions for a Parallelogram
Rectangle, Rhombus, Square
Mid-Point Theorem
Converse of Mid-Point Theorem

Study Resources

Key Formulas & Identities

Formula / Rule Expression
Quad Angle Sum \(∠A + ∠B + ∠C + ∠D = 360°\)
Parallelogram: sides \(AB = CD, AD = BC\)
Parallelogram: ∠s \(∠A = ∠C, ∠B = ∠D\)
Parallelogram: ∠ sum \(∠A + ∠B = 180° \; (\text{co-interior)}\)
Diagonals bisect \(AO = OC, BO = OD\; (\text{O = intersection})\)
Rectangle diagonals \(AC = BD\; (\text{equal diagonals})\)
Rhombus diagonals \(AC ⊥ BD\; (\text{perpendicular diagonals})\)
Mid-Point Theorem \(DE ∥ BC\; \&\; DE = BC/2\; (\text{D, E midpoints of AB, AC})\)

Important Points to Remember

Angle sum of any quadrilateral = 360°. This follows by dividing into two triangles.
A parallelogram has: opposite sides equal and parallel, opposite angles equal, diagonals bisect each other.
A rectangle is a parallelogram with all angles 90°; a rhombus has all sides equal; a square is both.
Mid-Point Theorem: the segment joining midpoints of two sides of a triangle is parallel to the third side and half its length.
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