Class IX · Chapter 4 Chemistry

CHAPTER 04

Structure of the Atom

Electrons, Protons, Neutrons & Shells

Inside every atom is a tiny nucleus surrounded by electrons in shells — Thomson, Rutherford, and Bohr each peeled back another layer.

\(Mass Number A = Z + N | Shell capacity = 2n²\)
9 CBSE Marks
Difficulty
10 Topics
Very High Board Weight

Topics Covered

10 key topics in this chapter

Charged Particles in Matter
Thomson's Atomic Model
Rutherford's Experiment
Rutherford's Atomic Model
Bohr's Atomic Model
Electrons, Protons & Neutrons
Electronic Configuration
Valency
Atomic Number & Mass Number
Isotopes & Isobars

Study Resources

Key Concepts

01. Discovery of Sub-atomic Particles

J.J. Thomson (1897) discovered electrons using cathode ray tube — negatively charged. E. Goldstein (1886) discovered protons (canal rays — positively charged). J. Chadwick (1932) discovered neutrons — neutral.

02. Thomson's Plum-Pudding Model

Thomson proposed an atom as a uniform sphere of positive charge with electrons (plums) embedded in it. This model could not explain Rutherford's scattering results.

03. Rutherford's Gold Foil Experiment

Most α-particles passed straight through, some deflected, very few bounced back. Conclusion: atom is mostly empty space with a tiny, dense, positive nucleus. Limitation: could not explain stable orbits.

04. Bohr's Atomic Model

Electrons revolve in fixed circular orbits (shells) without radiating energy. Each shell has a fixed energy. Electrons jump between shells by absorbing/emitting quanta of energy. Shells are labelled K, L, M, N (n=1,2,3,4).

05. Electronic Configuration

Maximum electrons in shell n = 2n². So K(n=1) → 2, L(n=2) → 8, M(n=3) → 18. Outermost shell can hold max 8 electrons. Configuration is written as 2, 8, 3 (for Al, Z=13).

06. Atomic Number, Mass Number, Isotopes & Isobars

Atomic number Z = number of protons. Mass number A = protons + neutrons (Z + N). Isotopes: same Z, different A (¹H, ²H, ³H). Isobars: same A, different Z (⁴⁰Ca and ⁴⁰Ar).

Formulas at a Glance

# Name Expression Notes
01 Mass Number A = Z + N Protons (Z) + Neutrons (N)
02 Number of Neutrons N = A − Z From mass and atomic numbers
03 Shell Capacity 2n² Max electrons in nth shell
04 Valency (metal/nonmetal) V = outermost electrons (or 8 − outermost) For electrons < 4, V = e⁻; for > 4, V = 8 − e⁻

Important Notes

Protons and neutrons are in the nucleus; electrons orbit outside in shells. Proton = positive, Electron = negative, Neutron = neutral.
For a neutral atom: number of protons = number of electrons.
Isotopes of an element have the same chemical properties (same Z, same electronic configuration) but different physical properties (different mass).
Isobars have different chemical properties because they have different atomic numbers and different electronic configurations.
Valency is the combining capacity of an element and equals the number of electrons in the outermost shell (or 8 minus that number if > 4).

Exam Tips & Common Mistakes

1

For "draw the electronic configuration of element X" questions: fill shells as 2, 8, 8… until electrons run out.

2

Distinguish Isotopes vs Isobars: same Atomic number = Isotopes; same Mass number = Isobars (one-mark distinction).

3

Rutherford's experiment — know the three observations and the three corresponding conclusions. This is a 5-mark question pattern.

4

Bohr's model limitation: applies accurately only to hydrogen atom; fails for multi-electron atoms.

5

Valency of elements with 5, 6, 7 outer electrons = 3, 2, 1 respectively (8 - outer electrons).

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